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SIMPLE PROBLEMS
1.Find S.I on Rs68000 at 16 2/3% per annum for 9months.
Sol:- P=68000
R=50/3% p.a
T=9/12 years=4/3 years
S.I=(P*R*T)/100
=(68000*(50/3)*(3/4)*(1/100))
=Rs 8500
Note:- If months are given we have to converted into years by dividing
12 ie., no.of months/12=years
(2)Find S.I on Rs3000 at 18% per annum for the period from 4th Feb to 18th April 1995
Sol:- Time=(24+31+18)days
=73 days
=73/365=1/5 years
P= Rs 3000
R= 18% p.a
S.I = (P*R*T)/100
=(3000*18*1/5*1/100)
=Rs 108
Remark:- The day on which money is deposited is not counted while the day on which money is withdrawn is counted.
3. In how many years will a sum of money becomes triple at 10% per annum.
Sol:- Let principal =P
S.I = 2P
S.I = (P*T*R)/100
2P = (P*T*10)/100
T = 20 years
Note:-(I) Total amount = Principal + S.I
(2) If sum of money becomes double means Total amount or Sum
= Principal + S.I
= P + P = 2P
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