| BACK Problems: 1.(5004 /139) – 6= ? Sol: Expression = 5004/ 139 – 6 = 36 – 6 = 30; Ans : 30 2.What mathematical operations should come at the place of ? in the equation : (2 ? 6 – 12 / 4 + 2 = 11) ? Sol: 2 ? 6 = 11 + 12 / 4 – 2 = 11 + 3 – 2 = 12 2 * 6 = 12 Ans : * 3.( 8 / 88) * 8888088 = ? Sol : (1/11) * 8888088 = 808008 Ans: 808008 4.How many 1/8's are there in 371/2 ? Sol: (371/2) /(1/8)= (75/2) /(1/8) = 300 Ans: 300 5.Find the values of 1/2*3 +1/3*4 +1/4*5+ .................+1/9*10 ? Sol: 1/2*3 +1/3*4+1/4*5+ ..................+1/9*10 = [½ -1/3] +[ 1/3 – ¼] + [¼- 1/5] +...............+[1/9-1/10] = [ ½ – 1/10] = 4/15 = 2/5 Ans : 2/5 6.The value of 999 of 995/999* 999 is: Sol: [1000- 4/1000]*999 = 999000-4 = 998996 7.Along a yard 225m long, 26 trees are planted at equal distance, one tree being at each end of the yard. what is the distance between two consecutive trees ? Sol: 26 trees have 25 gaps between them. Hence , required distance = 225/ 25 m= 9m Ans: 9m 8.In a garden , there are 10 rows and 12 columns of mango trees. the distance between the two trees is 2 m and a distance of one meter is left from all sides of the boundary of the length of the garden is : Sol: Each row contains 12 plants. leaving 2 corner plants, 10 plants in between have 10 * 2 meters and 1 meter on each side is left. length = (20 + 2) m = 22m 9.Eight people are planning to share equally the cost of a rental car , if one person with draws from the arrangement and the others share equally the entire cost of the car, then the share of each of the remaining persons increased by? Sol: Original share of one person = 1/8 new share of one person = 1/7 increase = 1/7 – 1/8 = 1/56 required fractions = (1/56)/(1/8) = 1/7 10.A piece of cloth cost Rs 35. if the length of the piece would have been 4m longer and each meter cost Re 1 less , the cost would have remained unchanged. how long is the piece? Sol: Left the length of the piece be x m. then, cost of 1m of piece = Rs [35 / x] 35/ x – 35 /x+4 = 1 x + 4 – x = x(x+ 4)/35 x2 + 4x – 140 = 0 x= 10 Ans : 10 m 11.A man divides Rs 8600 among 5sons, 4 daughters and 2 nephews. if each daughter receives four times as much as each nephew, and each son receives five as much as each nephew. how much does each daughter receive ? Sol: Let the share of each nephew be Rs x. then, share of each daughter Rs 4x. share of each son = 5x Rs so, 5 *5x+ 4 * 4x + 2x =8600 2x + 16x + 25x= 8600 43x = 8600 x = 200 share of each daughter = 4 * 200 = Rs 800 12.A man spends 2/5 of his salary on house rent, 3/10 of his salary on food, and 1/8 of his salary on conveyance. if he has Rs 1400 left with him, find his expenditure on food and conveyance? Sol: Part of the salary left = 1-[2/5 +3/10+1/9] = 1- 33/40 =7/40 Let the monthly salary be rs x then, 7/40 of x = 1400 x= [1400*40]/7 x= 8000 Expenditure on food = 3/10*8000 =Rs 2400 Expenditure on conveyance= 1/8*8000 =Rs 1000 BACK |